Integrand size = 24, antiderivative size = 168 \[ \int \sin ^3\left (a+\frac {1}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=-\frac {9}{16} e^{a \sqrt {-\frac {1}{n^2}} n} \sqrt {-\frac {1}{n^2}} n x \left (c x^n\right )^{\left .-\frac {1}{3}\right /n}+\frac {9}{32} e^{-a \sqrt {-\frac {1}{n^2}} n} \sqrt {-\frac {1}{n^2}} n x \left (c x^n\right )^{\left .\frac {1}{3}\right /n}-\frac {1}{16} e^{-3 a \sqrt {-\frac {1}{n^2}} n} \sqrt {-\frac {1}{n^2}} n x \left (c x^n\right )^{\frac {1}{n}}+\frac {1}{8} e^{3 a \sqrt {-\frac {1}{n^2}} n} \sqrt {-\frac {1}{n^2}} n x \left (c x^n\right )^{-1/n} \log (x) \]
-9/16*exp(a*n*(-1/n^2)^(1/2))*n*x*(-1/n^2)^(1/2)/((c*x^n)^(1/3/n))+9/32*n* x*(c*x^n)^(1/3/n)*(-1/n^2)^(1/2)/exp(a*n*(-1/n^2)^(1/2))-1/16*n*x*(c*x^n)^ (1/n)*(-1/n^2)^(1/2)/exp(3*a*n*(-1/n^2)^(1/2))+1/8*exp(3*a*n*(-1/n^2)^(1/2 ))*n*x*ln(x)*(-1/n^2)^(1/2)/((c*x^n)^(1/n))
\[ \int \sin ^3\left (a+\frac {1}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=\int \sin ^3\left (a+\frac {1}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx \]
Time = 0.35 (sec) , antiderivative size = 144, normalized size of antiderivative = 0.86, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {4986, 4992, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \sin ^3\left (a+\frac {1}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx\) |
\(\Big \downarrow \) 4986 |
\(\displaystyle \frac {x \left (c x^n\right )^{-1/n} \int \left (c x^n\right )^{\frac {1}{n}-1} \sin ^3\left (a+\frac {1}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right )d\left (c x^n\right )}{n}\) |
\(\Big \downarrow \) 4992 |
\(\displaystyle \frac {1}{8} \sqrt {-\frac {1}{n^2}} x \left (c x^n\right )^{-1/n} \int \left (-3 e^{a \sqrt {-\frac {1}{n^2}} n} \left (c x^n\right )^{\frac {2}{3 n}-1}+3 e^{-a \sqrt {-\frac {1}{n^2}} n} \left (c x^n\right )^{\frac {4}{3 n}-1}-e^{-3 a \sqrt {-\frac {1}{n^2}} n} \left (c x^n\right )^{\frac {2}{n}-1}+\frac {e^{3 a \sqrt {-\frac {1}{n^2}} n} x^{-n}}{c}\right )d\left (c x^n\right )\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {1}{8} \sqrt {-\frac {1}{n^2}} x \left (c x^n\right )^{-1/n} \left (-\frac {9}{2} n e^{a \sqrt {-\frac {1}{n^2}} n} \left (c x^n\right )^{\left .\frac {2}{3}\right /n}+\frac {9}{4} n e^{-a \sqrt {-\frac {1}{n^2}} n} \left (c x^n\right )^{\left .\frac {4}{3}\right /n}-\frac {1}{2} n e^{-3 a \sqrt {-\frac {1}{n^2}} n} \left (c x^n\right )^{2/n}+e^{3 a \sqrt {-\frac {1}{n^2}} n} \log \left (c x^n\right )\right )\) |
(Sqrt[-n^(-2)]*x*((-9*E^(a*Sqrt[-n^(-2)]*n)*n*(c*x^n)^(2/(3*n)))/2 + (9*n* (c*x^n)^(4/(3*n)))/(4*E^(a*Sqrt[-n^(-2)]*n)) - (n*(c*x^n)^(2/n))/(2*E^(3*a *Sqrt[-n^(-2)]*n)) + E^(3*a*Sqrt[-n^(-2)]*n)*Log[c*x^n]))/(8*(c*x^n)^n^(-1 ))
3.1.43.3.1 Defintions of rubi rules used
Int[Sin[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*(d_.)]^(p_.), x_Symbol] :> Si mp[x/(n*(c*x^n)^(1/n)) Subst[Int[x^(1/n - 1)*Sin[d*(a + b*Log[x])]^p, x], x, c*x^n], x] /; FreeQ[{a, b, c, d, n, p}, x] && (NeQ[c, 1] || NeQ[n, 1])
Int[((e_.)*(x_))^(m_.)*Sin[((a_.) + Log[x_]*(b_.))*(d_.)]^(p_.), x_Symbol] :> Simp[(m + 1)^p/(2^p*b^p*d^p*p^p) Int[ExpandIntegrand[(e*x)^m*(E^(a*b*d ^2*(p/(m + 1)))/x^((m + 1)/p) - x^((m + 1)/p)/E^(a*b*d^2*(p/(m + 1))))^p, x ], x], x] /; FreeQ[{a, b, d, e, m}, x] && IGtQ[p, 0] && EqQ[b^2*d^2*p^2 + ( m + 1)^2, 0]
\[\int {\sin \left (a +\frac {\ln \left (c \,x^{n}\right ) \sqrt {-\frac {1}{n^{2}}}}{3}\right )}^{3}d x\]
Result contains complex when optimal does not.
Time = 0.25 (sec) , antiderivative size = 84, normalized size of antiderivative = 0.50 \[ \int \sin ^3\left (a+\frac {1}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=\frac {1}{32} \, {\left (9 i \, x^{\frac {4}{3}} e^{\left (\frac {2 \, {\left (3 i \, a n - \log \left (c\right )\right )}}{3 \, n}\right )} - 2 i \, x^{2} + 12 i \, e^{\left (\frac {2 \, {\left (3 i \, a n - \log \left (c\right )\right )}}{n}\right )} \log \left (x^{\frac {1}{3}}\right ) - 18 i \, x^{\frac {2}{3}} e^{\left (\frac {4 \, {\left (3 i \, a n - \log \left (c\right )\right )}}{3 \, n}\right )}\right )} e^{\left (-\frac {3 i \, a n - \log \left (c\right )}{n}\right )} \]
1/32*(9*I*x^(4/3)*e^(2/3*(3*I*a*n - log(c))/n) - 2*I*x^2 + 12*I*e^(2*(3*I* a*n - log(c))/n)*log(x^(1/3)) - 18*I*x^(2/3)*e^(4/3*(3*I*a*n - log(c))/n)) *e^(-(3*I*a*n - log(c))/n)
\[ \int \sin ^3\left (a+\frac {1}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=\int \sin ^{3}{\left (a + \frac {\sqrt {- \frac {1}{n^{2}}} \log {\left (c x^{n} \right )}}{3} \right )}\, dx \]
Time = 0.25 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.63 \[ \int \sin ^3\left (a+\frac {1}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=-\frac {4 \, c^{\frac {1}{3 \, n}} {\left (x^{n}\right )}^{\frac {1}{3 \, n}} \log \left (x\right ) \sin \left (3 \, a\right ) - 9 \, c^{\frac {5}{3 \, n}} x {\left (x^{n}\right )}^{\frac {2}{3 \, n}} \sin \left (a\right ) + 2 \, c^{\frac {7}{3 \, n}} e^{\left (\frac {\log \left (x^{n}\right )}{3 \, n} + 2 \, \log \left (x\right )\right )} \sin \left (3 \, a\right ) - 18 \, c^{\left (\frac {1}{n}\right )} x \sin \left (a\right )}{32 \, c^{\frac {4}{3 \, n}} {\left (x^{n}\right )}^{\frac {1}{3 \, n}}} \]
-1/32*(4*c^(1/3/n)*(x^n)^(1/3/n)*log(x)*sin(3*a) - 9*c^(5/3/n)*x*(x^n)^(2/ 3/n)*sin(a) + 2*c^(7/3/n)*e^(1/3*log(x^n)/n + 2*log(x))*sin(3*a) - 18*c^(1 /n)*x*sin(a))/(c^(4/3/n)*(x^n)^(1/3/n))
Exception generated. \[ \int \sin ^3\left (a+\frac {1}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=\text {Exception raised: NotImplementedError} \]
Exception raised: NotImplementedError >> unable to parse Giac output: ((-9 *i)*sageVARn^4*sageVARx*exp((-3*i)*sageVARa)*exp((sageVARn*abs(sageVARn)*l n(sageVARx)+abs(sageVARn)*ln(sageVARc))/sageVARn^2)+27*i*sageVARn^4*sageVA Rx*exp((-i)*sageVAR
Time = 27.26 (sec) , antiderivative size = 155, normalized size of antiderivative = 0.92 \[ \int \sin ^3\left (a+\frac {1}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=-x\,{\mathrm {e}}^{-a\,1{}\mathrm {i}}\,\frac {1}{{\left (c\,x^n\right )}^{\frac {\sqrt {-\frac {1}{n^2}}\,1{}\mathrm {i}}{3}}}\,\left (\frac {9\,n\,\sqrt {-\frac {1}{n^2}}}{64}-\frac {27}{64}{}\mathrm {i}\right )-x\,{\mathrm {e}}^{a\,1{}\mathrm {i}}\,{\left (c\,x^n\right )}^{\frac {\sqrt {-\frac {1}{n^2}}\,1{}\mathrm {i}}{3}}\,\left (\frac {9\,n\,\sqrt {-\frac {1}{n^2}}}{64}+\frac {27}{64}{}\mathrm {i}\right )+\frac {x\,{\mathrm {e}}^{-a\,3{}\mathrm {i}}\,\frac {1}{{\left (c\,x^n\right )}^{\sqrt {-\frac {1}{n^2}}\,1{}\mathrm {i}}}}{8\,n\,\sqrt {-\frac {1}{n^2}}+8{}\mathrm {i}}+\frac {x\,{\mathrm {e}}^{a\,3{}\mathrm {i}}\,{\left (c\,x^n\right )}^{\sqrt {-\frac {1}{n^2}}\,1{}\mathrm {i}}}{8\,n\,\sqrt {-\frac {1}{n^2}}-8{}\mathrm {i}} \]
(x*exp(-a*3i)/(c*x^n)^((-1/n^2)^(1/2)*1i))/(8*n*(-1/n^2)^(1/2) + 8i) - x*e xp(a*1i)*(c*x^n)^(((-1/n^2)^(1/2)*1i)/3)*((9*n*(-1/n^2)^(1/2))/64 + 27i/64 ) - x*exp(-a*1i)/(c*x^n)^(((-1/n^2)^(1/2)*1i)/3)*((9*n*(-1/n^2)^(1/2))/64 - 27i/64) + (x*exp(a*3i)*(c*x^n)^((-1/n^2)^(1/2)*1i))/(8*n*(-1/n^2)^(1/2) - 8i)